(x^2+12x+12)=(x+2)

Solution for (x^2+12x+12)=(x+2) equation:

(x^2+12x+12)=(x+2)

We move all terms to the left:

(x^2+12x+12)-((x+2))=0

We get rid of parentheses

x^2+12x-((x+2))+12=0


We calculate terms in parentheses: -((x+2)), so:

(x+2)

We get rid of parentheses

x+2

Back to the equation:

-(x+2)


We get rid of parentheses

x^2+12x-x-2+12=0

We add all the numbers together, and all the variables

x^2+11x+10=0

a = 1; b = 11; c = +10;
Δ = b2-4ac
Δ = 112-4·1·10
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-9}{2*1}=\frac{-20}{2}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+9}{2*1}=\frac{-2}{2}
=-1
$